21x^2+20x+19=0

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Solution for 21x^2+20x+19=0 equation: 



21x^2+20x+19=0

a = 21; b = 20; c = +19;
Δ = b2-4ac
Δ = 202-4·21·19
Δ = -1196
Delta is less than zero, so there is no solution for the equation

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